(cos(3x)+isin(3x))/(cos(x)+isin(x))
Given expression is: "\\frac{(cos(3x)+isin(3x))}{(cos(x)+isin(x))}"
Using Euler form, this can simplify to: "\\frac{e^{i(3x)}}{e^{i(x)}}\\\\"
"=e^{i(2x)}\\\\\n=cos(2x)+isin(2x)"
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