"P=20 \\\\\n20 = \\frac{300}{3 +17e^{-0.0625x}} \\\\\n2 = \\frac{30}{3 +17e^{-0.0625x}} \\\\\n15 = 3 +17e^{-0.0625x} \\\\\n17e^{-0.0625x} = 12 \\\\\ne^{-0.0625x} = \\frac{12}{17} \\\\\n-0.0625x = ln(\\frac{12}{17}) \\\\\nx = \\frac{-0.348306}{-0.0625} \\\\\nx = 5.572 \u2248 6"
Comments
Leave a comment