P=2020=3003+17e−0.0625x2=303+17e−0.0625x15=3+17e−0.0625x17e−0.0625x=12e−0.0625x=1217−0.0625x=ln(1217)x=−0.348306−0.0625x=5.572≈6P=20 \\ 20 = \frac{300}{3 +17e^{-0.0625x}} \\ 2 = \frac{30}{3 +17e^{-0.0625x}} \\ 15 = 3 +17e^{-0.0625x} \\ 17e^{-0.0625x} = 12 \\ e^{-0.0625x} = \frac{12}{17} \\ -0.0625x = ln(\frac{12}{17}) \\ x = \frac{-0.348306}{-0.0625} \\ x = 5.572 ≈ 6P=2020=3+17e−0.0625x3002=3+17e−0.0625x3015=3+17e−0.0625x17e−0.0625x=12e−0.0625x=1712−0.0625x=ln(1712)x=−0.0625−0.348306x=5.572≈6
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