Question #245707

The first terms of an A.P and G.P are each 2/3. Their common and difference and

common ratio are each X and the sum of their first three terms are also equal.

Find the two possible values of X


Expert's answer

a=b=23a=b=\dfrac{2}{3}

a+a+x+a+2x=b+bx+bx2a+a+x+a+2x=b+bx+bx^2

3(23)+3x=23(1+x+x2)3(\dfrac{2}{3})+3x=\dfrac{2}{3}(1+x+x^2)

6+9x=2+2x+2x26+9x=2+2x+2x^2

2x2−7x−4=02x^2-7x-4=0

D=(−7)2−4(2)(−4)=81D=(-7)^2-4(2)(-4)=81

x=7±812(2)x=\dfrac{7\pm \sqrt{81}}{2(2)}

x1=7−94=−12x_1=\dfrac{7- 9}{4}=-\dfrac{1}{2}

x2=7+94=4x_2=\dfrac{7+ 9}{4}=4


x∈{−12,4}x\in\{-\dfrac{1}{2}, 4\}


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