Answer to Question #245701 in Algebra for Sebastian

Question #245701

Simply and express your answer in a form that is free of radicals in the denominator

3/2+√3-4/1-√2

Expert's answer

"\\dfrac{3}{2+\\sqrt{3}}-\\dfrac{4}{1-\\sqrt{2}}=\\dfrac{2(2-\\sqrt{3})}{4-3}-\\dfrac{4(1+\\sqrt{2})}{1-2}"

"=4-2\\sqrt{3}+4-4\\sqrt{2}=8-2\\sqrt{3}-4\\sqrt{2}"

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