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Answer to Question #24515 in Algebra for brittany
Question #24515
The formula for final velocity of an object starting from zero and undergoing constant acceleration is v=1/2at^2, what is the final velocity if a car is accelerating at 4 m/s^2 for 5 seconds
Expert's answer
This formula for distance:
s=1/2at^2
s - distance
a - acceleration
t - time
The formula for final velocity of an object starting from zero and undergoing constant acceleration is:
v=a*t
In our case:
a=4 m/s^2,
t= 5 sec,
Therefore:
v =a*t = 4m/s^2 * 5s = 20 m/sec = 20 m/sec &
s=1/2at^2
s - distance
a - acceleration
t - time
The formula for final velocity of an object starting from zero and undergoing constant acceleration is:
v=a*t
In our case:
a=4 m/s^2,
t= 5 sec,
Therefore:
v =a*t = 4m/s^2 * 5s = 20 m/sec = 20 m/sec &
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Comments
Dear Ivan, please use the panel for submitting a new question.
The formula for final velocity of an object starting from zero and undergoing constant acceleration is v = 1/2 * a * t ^ 2 What is the time it will take a car accelerating 4 m/s ^ 2 ? 50 m/s
Dear visitor, please use panel for submitting new questions
The formula for final velocity of an object starting from zero and undergoing constant acceleration is v=1/2at^2, what is the time it will take a car accelerating at 4 m/s^2 to reach 50m/s?
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