The formula for final velocity of an object starting from zero and undergoing constant acceleration is v=1/2at^2, what is the final velocity if a car is accelerating at 4 m/s^2 for 5 seconds
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Expert's answer
2013-02-27T05:22:53-0500
This formula for distance: s=1/2at^2 s - distance a - acceleration t - time The formula for final velocity of an object starting from zero and undergoing constant acceleration is: v=a*t In our case: a=4 m/s^2, t= 5 sec, Therefore: v =a*t = 4m/s^2 * 5s = 20 m/sec = 20 m/sec &
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Ivan
10.04.21, 00:32
The formula for final velocity of an object starting from zero and
undergoing constant acceleration is v = 1/2 * a * t ^ 2 What is the
time it will take a car accelerating 4 m/s ^ 2 ? 50 m/s
Assignment Expert
09.05.17, 19:48
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Kitten
09.05.17, 17:19
The formula for final velocity of an object starting from zero and
undergoing constant acceleration is v=1/2at^2, what is the time it
will take a car accelerating at 4 m/s^2 to reach 50m/s?
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Dear Ivan, please use the panel for submitting a new question.
The formula for final velocity of an object starting from zero and undergoing constant acceleration is v = 1/2 * a * t ^ 2 What is the time it will take a car accelerating 4 m/s ^ 2 ? 50 m/s
Dear visitor, please use panel for submitting new questions
The formula for final velocity of an object starting from zero and undergoing constant acceleration is v=1/2at^2, what is the time it will take a car accelerating at 4 m/s^2 to reach 50m/s?
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