The 5th term of a geometric Sequence is 8 and the 9th term Is 16128.find the first term
First term GP=aSecond term=arThird term=ar25th term=ar49th term=ar8ar4=8ar8=16128a=16128r816128r8×r4=8First \ term \ GP = a\\ Second\ term = ar\\ Third \ term = ar\\^2\\ 5th\ term = ar\\^4\\ 9th\ term = ar\\^8\\ ar\\^4 = 8\\ ar\\^8 = 16128 \\ a = \frac{16128}{r\\^8}\\ \frac{16128}{r\\^8} \times r\\^4 = 8First term GP=aSecond term=arThird term=ar25th term=ar49th term=ar8ar4=8ar8=16128a=r816128r816128×r4=8
16128r4=88r4=16128161288=r42016=r4r=6.70a=8r4a=8(6.7)4a=0.00397\frac{16128}{r\\^4} = 8 \\ \\ 8r\\^4 = 16128 \\ \frac{16128}{8} = r\\^4 \\ 2016 = r\\^4 \\ r = 6.70 \\a = \frac{8}{r\\^4} \\ a = \frac{8}{(6.7)\\^4} \\ a = 0.00397r416128=88r4=16128816128=r42016=r4r=6.70a=r48a=(6.7)48a=0.00397
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