Question

2c). Solve each of the following

I) x^2=72

II) (3n-1)^2=26

Answer 1

i) $x^2=72\to x=\sqrt{72}, x=-\sqrt{72}.$

ii) $(3n-1)^2=26\to 3n-1=\sqrt{26}\to$$n=\frac{\sqrt{26}+1}{3}, n=-\frac{\sqrt{26}+1}{3}$ .