C)
h(X)=ax^3-x^2-5x+b, where a and b are constants. For h(X) divide by (X+2) the remainder is 40 and for h(X) divided by (x-2) the remainder is 36. Find the value of a and b.
h(−2)=40→−8a−4+10+b=40→8a−b=−34.h(-2)=40\to -8a-4+10+b=40\to 8a-b=-34.h(−2)=40→−8a−4+10+b=40→8a−b=−34.
h(2)=36→8a−4−10+b=36→8a+b=50.h(2)=36\to 8a-4-10+b=36\to 8a+b=50.h(2)=36→8a−4−10+b=36→8a+b=50.
a=50−3416=1.a=\frac{50-34}{16}=1.a=1650−34=1.
b=50−1∗8=42.b=50-1*8=42.b=50−1∗8=42.
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