Let ADβtraveler movement by car
point B -call from uncle Ford
AByββdistance traveled or projection on an axis Y
AByβ=40km
tABβ=2h
taxi speed :
vtxβ=tABβAByββ=240β=20hkmβ
point C -uncle Ford meeting :
tACβ=tABβ+0.5=2.5h
ACyβ=vtxβtACβ=2.5β20=50km
point D -end of taxi ride :
tAΠβ=tAΠ‘β+1=3.5h
ADyβ=vtxβtADβ=2.5β20=70km
the tangent of the slope of a straight line with uniform motion
is numerically equal to the speed
tan(AD)=20
tan(DE)=hDEβDEyββ=1050β=5
Answer:
angle of inclination of straight lines
tan(AD)=20
tan(DE)=5
uncle Ford meeting distance :ACyβ=50km
distance where they started to walk.ADyβ=70km
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