Let AD−traveler movement by car
point B -call from uncle Ford
ABy−distance traveled or projection on an axis Y
ABy=40km
tAB=2h
taxi speed :
vtx=tABABy=240=20hkm
point C -uncle Ford meeting :
tAC=tAB+0.5=2.5h
ACy=vtxtAC=2.5∗20=50km
point D -end of taxi ride :
tAВ=tAС+1=3.5h
ADy=vtxtAD=2.5∗20=70km
the tangent of the slope of a straight line with uniform motion
is numerically equal to the speed
tan(AD)=20
tan(DE)=hDEDEy=1050=5
Answer:
angle of inclination of straight lines
tan(AD)=20
tan(DE)=5
uncle Ford meeting distance :ACy=50km
distance where they started to walk.ADy=70km
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