Answer to Question #237440 in Algebra for Mr. Lee

Question

Tommy’s age is the sum of the ages of Carmen and Dennis.

Carmen’s age is 2 more than the sum of Dennis and Mark.

Dennis’ age is 4 times Mark’s age. The sum of all four ages is

42. How old is Mark?

Answer 1

let Mark's $=M$

Therefore, Dennis' age $=4M$

Carmen's age $= [2+(4M+M)]=2+5M$

Tommy's age$=(2+5M)+(4M)=2+9M$

Now,

$M+4M+2+5M+2+9M=42$

$19M=38$

$M=\frac{38}{19}=2$

Therefore, Mark is 2 years old.