The first tern of an A.P. is 2 and the 6th term is 12. Find the
sum of the first 12 terms.
a1+(n−1)d.....Apseriesa1 +(n-1)d.....Ap seriesa1+(n−1)d.....Apseries
sumsumsum
sn=0.5n(2a+(n−1)d)sn = 0.5n(2a+(n-1)d)sn=0.5n(2a+(n−1)d)
a1=2a1 = 2a1=2
a1+5d=12a1 + 5d = 12a1+5d=12
d=2d= 2d=2
0.5∗12(2∗2+(12−1)2)0.5*12(2*2 + (12-1)2)0.5∗12(2∗2+(12−1)2)
sum=156sum = 156sum=156
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