Polynomial Inequalities:
8) x^2 + 7x < -12
show number line test and answer in interval notation
x2+7x<−12⇒x2+7x+12<0⇒x2+3x+4x+12<0⇒x(x+3)+4(x+3)<0⇒(x+3)(x+4)<0x^2+7x<-12\\ \Rightarrow x^2+7x+12<0\\ \Rightarrow x^2+3x+4x+12<0\\ \Rightarrow x(x+3)+4(x+3)<0\\ \Rightarrow (x+3)(x+4)<0\\x2+7x<−12⇒x2+7x+12<0⇒x2+3x+4x+12<0⇒x(x+3)+4(x+3)<0⇒(x+3)(x+4)<0
∴x∈(−4,−3)\therefore x\in(-4,-3)∴x∈(−4,−3)
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