One number is four times another number. Determine the two numbers of the sum of their reciprocals is 5/16
Let's take the two numbers to be xxx and yyy
x=4y1x+1y=516x=4y\\\frac{1}{x}+\frac{1}{y}=\frac{5}{16}x=4yx1+y1=165
Substitute for xxx
14y+1y=5161+44y=51654y=516y=4x=4yx=4(4)x=16\frac{1}{4y}+\frac{1}{y}=\frac{5}{16}\\\frac{1+4}{4y}=\frac{5}{16}\\\frac{5}{4y}=\frac{5}{16}\\y=4\\x=4y\\x=4(4)\\x=164y1+y1=1654y1+4=1654y5=165y=4x=4yx=4(4)x=16
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