Question #229170

Assessment

Solve the following.

1. The perimeter of a rectangle is 24 cm. Express the area of the rectangle in terms of the width x.

2. The area of a rectangle is 85 cm. Express the perimeter of the rectangle as a function of the width x.

3. A piece of wire y cm long is bent into a circle. Express the area of the circle as a function of the circumference y.

4.  Express the length of the radius of a circle as a function of the 

5. Express the length of the diameter of a circle as a function of the circumference.

6.The perimeter of a rectangle is 50 centimeters. Express its area A as a function of the length x.

7. A wire of length x is bent into the shape of a square. Express the area of the square as a function of x. 


1
Expert's answer
2021-08-25T05:36:45-0400

1.WidthWidth == xx

Perimeter=2(L+W)Perimeter=2(L+W)

Length=12xLength=12-x

Area of a rectangle is represented as: L×WL\times W

Area=x(12x)Area=x(12-x)


Area=12xx2Area=12x-x^2


2.Width=xWidth=x

Area=L×WArea=L\times W

Length=85xLength=\frac{85}{x}

Perimeter=2(85x+x)Perimeter=2(\frac{85}{x}+x)


Perimeter=170x+2xPerimeter=\frac{170}{x}+2x


3.Circumference=2πrCircumference=2\pi r

y=2πry=2\pi r

r=y2πr=\frac{y}{2\pi}

Area=πr2Area=\pi r^2

Area=π×(y2π)2Area=\pi \times(\frac{y}{2\pi})^2

Area=π×(y24π2)Area=\pi \times(\frac{y^2}{4\pi^2})


Area=y24πArea=\frac{y^2}{4\pi}

4.Circumference=2πrCircumference=2\pi r

y=2πry=2\pi r


r=y2πr=\frac{y}{2\pi}


5. r=y2πr=\frac{y}{2\pi}

diameter=r+r=2rdiameter=r+r=2r

2r=2(y2π)2r=2(\frac{y}{2\pi})


2r=yπ2r=\frac{y}{\pi}


6.Length=xLength=x

Width=25xWidth=25-x

A=L×WA=L\times W

A=x(25x)A=x(25-x)


A=25xx2A=25x-x^2


7.PerimeterPerimeter ofof aa square=xsquare=x

Since all sides of a square are equal:

LengthLength ofof aa sqaure=x4sqaure=\frac{x}{4}

Area=Side×Side=S×SArea=Side\times Side=S\times S

Area=x4×x4Area=\frac{x}{4} \times \frac{x}{4}


Area=x216Area=\frac{x^2}{16}


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