, In a cartesian plane (OXY) the solution of the equation e2x – 2ex + 1 = 0 represent,
A. A point
B. A line
C. A circle
The equation "e^{2x}-2e^x+1=0" is equivalent to the equation "(e^x-1)^2=0." It follows that "e^x-1=0," and hence "e^x=1." We conclude that the point "x=0" is a unique solution of the equation.
Answer: A
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