Question

6, Solve the inequalitThe catheti of a triangle has length 4m. If the hypotenuse of the triangle is 9m, that is the projection of this catheti on the hypotenuse.

A.     16/9

B.     4/3

C.     4y tan(x+ ∏/3) ≥ √3 

Answer 1

Right triangle $ABC$

$$BC=4\ m,AB=9\ m$$ $$\cos \theta=\dfrac{BC}{AB}=\dfrac{4\ m}{9\ m}=\dfrac{4}{9}$$

$BD=$ projection of $BC$ on $AB$

$$BD=BC\cos\theta=(4\ m)(\dfrac{4}{9})=\dfrac{16}{9}\ m$$

The projection of this catheti on the hypotenuse is

A.     16/9