What is the 20th term of the sequence: 1,1/3, . . . . . .,n +2/ 2n^2 + 3n - 2
20th term,
an=n+22n2+3n−2a20=20+22(20)2+3(20)−2a20=139a_n=\frac{n+2}{2n^2+3n-2}\\ a_{20}=\frac{20+2}{2(20)^2+3(20)-2}\\ a_{20}=\frac{1}{39}\\an=2n2+3n−2n+2a20=2(20)2+3(20)−220+2a20=391
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