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Answer to Question #22637 in Algebra for ekra
Question #22637
If R is a ring with identity, then prove that
<a>l ={ ta ; tЄR } = Ra
<a>r ={ at ; tЄR } = aR
<a>={ ∑_finit^n▒sia t I ; si ,ti ЄR} = RaR
<a>l ={ ta ; tЄR } = Ra
<a>r ={ at ; tЄR } = aR
<a>={ ∑_finit^n▒sia t I ; si ,ti ЄR} = RaR
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