Answer to Question #223998 in Algebra for Asi

Question

Translate into algebraic equation
35/5 + 13= 20

Answer 1

$Translate \space into \space algebraic \space equation\\ solution\\ given\\ \frac{35}{5} \space + \space 13= \space 20...eq(A)\\ we \space want \space to \space change \space it \space into \space algebraic \space equation\\ ---------------------------------\\ algebric \space equation \space definition\\ in \space mathematics \space , \space an \space algebraic \space equation \space is \space an \space expression\\ \space built \space up \space from \space integer \space constants \space , \space \\ variables \space and \space the \space algebraic \space operations.\\ ----------------------------------\\ in \space the \space question, \space we \space have \space a \space single \space equation \space \\ then \space we \space can \space create \space only \space single \space variable \space algebraic \space equation\\ ----------------------------------\\ case(i) \space if \space we \space take \space 35 \space as \space a \space variable:-\\ substitute \space 35 \space = \space x \space in \space the \space eq(A)\\ we \space get\\ \frac{x}{5}+13=20\\ simplify\\ x+(5×13)=(5×20)\\ x+65=100\\ this \space represents \space an \space algebraic \space equation\\ -------------------------------------\\ case(ii) \space if \space we \space take \space 13 \space as \space a \space variable:-\\ substitute \space 13 \space = \space x \space in \space the \space eq(A)\\ we \space get\\ \frac{35}{5}+x=20\\ simplify\\ 35+(5×x)=(5×20)\\ 5x+35=100\\ this \space represents \space an \space algebraic \space equation\\ -------------------------------------\\ case(iii) \space if \space we \space take \space 20 \space as \space a \space variable:-\\ substitute \space 20 \space = \space x \space in \space the \space eq(A)\\ we \space get\\ \frac{35}{5}+13=x\\ simplify\\ 35+(5×13)=(5×x)\\ 35+65=5x\\ 100=5x\\ this \space represents \space an \space algebraic \space equation\\ -------------------------------------\\ case(iv) \space if \space we \space take \space 5 \space as \space a \space variable:-\\ substitute \space 5 \space = \space x \space in \space the \space eq(A)\\ we \space get\\ \frac{35}{x}+13=20\\ simplify\\ 35+(x×13)=(20×x)\\ 35+13x=20x\\ this \space represents \space an \space algebraic \space equation\\ \space$