Answer to Question #222519 in Algebra for Jak

Question

The equation of the straight line with gradient 2 and passing through the point with coordinate (-2, 1) 

Answer 1

$\text{Gradient = }\frac{y-y_1}{x-x_1} \implies \text{gradient = 2, $y_1 = 1 $ and $x_1 = -2$} \\ \implies \frac{y-1}{x-(-2)} = \frac{y-1}{x+2} = 2 \implies y-1 = 2(x+2) = 2x + 2 \\ \implies y- 1 = 2x + 2 \implies y = 2x + 2+1 = 2x+ 3\\ \text{The required equation of line is: } y = 2x + 3$