Question

(√(c-5)² + (c²-2))= 23

Answer 1

$\sqrt{(c-5)^2+(c^2-2)}=23$

$(c-5)^2+(c^2-2)=23^2$

$2c^2-10c-506=0$

$c^2-5c-253=0$

$c_1=\frac{5+\sqrt{1037}}{2}$

$c_2=\frac{5-\sqrt{1037}}{2}$