a^3x+5/a^3x-1
Solution.
"a^{3x}+\\frac{5}{a^{3x}}-1=0; \\newline\nLets \\space a^{3x}=y; \\newline\n\\frac {y^{2}-y+5}{y}=0; \\newline\ny \\ne0; \\newline\nD=b^2-4ac; \\newline\nD=1-4*1*5=-19; \\newline\nD<0.\n\\newline"
In this problem there are no real zeros.
Answer: there are no real zeros.
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