Answer to Question #217424 in Algebra for Rayce

Question

A pair of shoes cost 32cedi more than a football if the cost of the pair of shoes is 95 cedis what is the cost of the football

Answer 1

We proceed if we consider S = price of a pair of shoes and F = price of a football:

$S = F + 32\,cedis \\S = 95 \,cedis \\\therefore F=S-32\,cedis \\ \implies F= 95 \,cedis- 32\,cedis=63\,cedis$

In conclusion, a football has a cost of 63 cedis.