Answer to Question #217348 in Algebra for Collins

Question #217348

Evaluate α given that α= [log(e²e^log2)/2]^1/2 .

Expert's answer

"\\alpha =[log(e^2e^{log2})\/2]^{1\/2}=[\\frac{log(e^2 2)}{2}]^{1\/2} = [\\frac{log(e^2)+log 2)}{2}]^{1\/2}"

"= [\\frac{2+log 2)}{2}]^{1\/2}=[1+\\frac{1}{2}log 2]^{1\/2}=\\sqrt{1+log(\\sqrt 2)}"

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