Evaluate α given that α= [log(e2elog2)/2]1/2 .
α=[log(e2elog2)/2]1/2=[log(e22)2]1/2=[log(e2)+log2)2]1/2\alpha =[log(e^2e^{log2})/2]^{1/2}=[\frac{log(e^2 2)}{2}]^{1/2} = [\frac{log(e^2)+log 2)}{2}]^{1/2}α=[log(e2elog2)/2]1/2=[2log(e22)]1/2=[2log(e2)+log2)]1/2
=[2+log2)2]1/2=[1+12log2]1/2=1+log(2)= [\frac{2+log 2)}{2}]^{1/2}=[1+\frac{1}{2}log 2]^{1/2}=\sqrt{1+log(\sqrt 2)}=[22+log2)]1/2=[1+21log2]1/2=1+log(2)
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments
Leave a comment