Answer to Question #217348 in Algebra for Collins

Question #217348

Evaluate α given that α= [log(e2elog2)/2]1/2 .


1
Expert's answer
2021-08-09T07:57:12-0400

α=[log(e2elog2)/2]1/2=[log(e22)2]1/2=[log(e2)+log2)2]1/2\alpha =[log(e^2e^{log2})/2]^{1/2}=[\frac{log(e^2 2)}{2}]^{1/2} = [\frac{log(e^2)+log 2)}{2}]^{1/2}


=[2+log2)2]1/2=[1+12log2]1/2=1+log(2)= [\frac{2+log 2)}{2}]^{1/2}=[1+\frac{1}{2}log 2]^{1/2}=\sqrt{1+log(\sqrt 2)}


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