Answer to Question #211521 in Algebra for Moe

Question #211521

Which of the following = (n+1)!/(n2)!(n+1)! / (n-2)!

  1. n(n1)(n2)n(n-1)(n-2)
  2. (n+1)n(n1)!(n+1)n(n-1)!
  3. n(n1)(n2)!n(n-1)(n-2)!
  4. (n+1)n(n1)(n + 1)n(n - 1)
  5. None of the above
1
Expert's answer
2021-06-30T16:50:12-0400
(n+1)!(n2)!=(n+1)(n)(n1)(n2)!(n2)!=\dfrac{(n+1)!}{(n-2)!}=\dfrac{(n+1)(n)(n-1)(n-2)!}{(n-2)!}=

=(n+1)n(n1)=(n+1)n(n-1)

4. (n+1)n(n1)(n+1)n(n-1)



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