y=(u-2)3 and u=1/2x=1
y=(u−2)3y=(u-2)^3y=(u−2)3
u=12x−1u=\frac{1}{2}x-1u=21x−1
y=(12x−1−2)3y=(\frac{1}{2}x-1-2)^3y=(21x−1−2)3
y=(12x−3)3y=(\frac{1}{2}x-3)^3y=(21x−3)3
But x=1
y=(12−3)3y=(\frac{1}{2}-3)^3y=(21−3)3
y=−1258y=-\frac{125}{8}y=−8125
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