Answer to Question #211323 in Algebra for Lebo

Question

(2x+5)(x²-2)=0

Answer 1

(2x+5)(x²-2)=0

Steps:

1. (2x+5)=0
2. 2x=-5
3. x₁= $-\frac{5}{2}$
4. (x²-2)=0
5. x²=2
6. x₂= $\sqrt{2}$
7. x₃= $-\sqrt{2}$

The solutions are:

x₁= $-\frac{5}{2}$ , x₂= $\sqrt{2}$ , x₃= $-\sqrt{2}$

Plotting: