Question #207240

the equation of the line that has a gradient of 3 and passes through the y-axis at (0,1)


1
Expert's answer
2021-07-16T01:23:26-0400

Gradient=ΔYΔXGradient =\frac {\Delta Y} {\Delta X}


3=y1x03=\frac {y-1}{x-0}


3x=y13x=y-1


Putting the equation in the form y=mx+c


y=3x+1y=3x+1


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