solving by elimination
3xxβ2yy=14...............................(1)4xxβ3yy=17...............................(2)
To eliminate xx multiply through eqn 1 by 4 and multiply through eqn 2 by 3
12xxβ8yy=5612xxβ9yy=51
Subtrating the second equation from the first equation of the previous system
yy=5
substituting the computed value in the equation 1
3xxβ2(5)=143xxβ10=143xx=14+103xx=24xx=324βxx=8
xx=8
yy=5
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