Answer to Question #207014 in Algebra for Jen

Question

TYPE A PROBLEM.

CHOOSE ONE INTEGER FROM THE FOLLOWING SET: -5 ≤ X ≤ 5. STATE THE INTEGER YOU CHOSE.

WHEN USING LONG DIVISION, WHAT BINOMIAL WOULD YOU DIVIDE BY TO DETERMINE IF THE INTEGER YOU CHOSE IS A ZERO FOR YOUR POLYNOMIAL?

DO THE LONG DIVISION

WRITE THE ANSWER TO THE LONG DIVISION PROBLEM IN THE FORM QUOTIENT + REMAINDER/DIVISOR

Answer 1

We have to perform long division

Let's take an equition

$9x^2+8x^2-4x^2-x+7$

We have to choose integer from the following set $:-5\leq X\leq 5$

$X=4$

Then, $x-4=0$

Now

$19x^3+84x^332+1327$

$\sqrt[x-4]{9x^2+8x^2-4x^2-x+7}$

$(19x^4-76x^3)+\\84x^3-4x^2-x+7\\84x^3-336x^2$ +

$332x^2-x+7\\332x^2-1328x$ +

$1327x+7\\1327x-5308=5315$

Hence

$Quotient+\frac{remainder}{divisor}$

So, $19x^3+84x^2+332x+1327+\frac{5315}{x-4}$

If I choose 0 integer for long Division then x=0

X-0=0 is the binomial

but I chose x=4 for my equition.