Answer to Question #20647 in Algebra for Javier
Ed has 4 more pretzels than Cal. They have 10 pretzels in all. How many pretzels doe Cal have?
1
2012-12-13T08:23:34-0500
Let Ed has E pretzels and Cal has C ones. Then we've got a system of linear equations:
E + C = 10, (1)
E - 4 = C. (2)
Let's solve it:
(1) ==> E + (E - 4) = 10,
or
2E = 14 ==> E = 7.
Therefore, Ed has 7 pretzels and Cal has C = 10 - 7 = 3 pretzels.
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