Answer to Question #203987 in Algebra for Snakho

Question #203987

Use the fact [x y 1]

[a1 b1 1] =0

[a2 b2 1]

To determine the equation of the line passing through the distinct points(a1, b1) and (a2, b2) where (.) stands for det.


1
Expert's answer
2021-06-07T13:27:24-0400


We have,

xx1a1b11a2b21=0 x(b1b2)y(a1a2)+b2a1a2b1=0x(b2b1)y(a2a1)+a2b1b2a1=0x(b2b1)+a2b1=y(a2a1)+b2a1Add a2b2 on both sides, we getx(b2b1)a2b2+a2b1=y(a2a1)b2(a2a1)(b2b1)(xa2)=(a2a1)(yb2) yb2b2b1=xa2a2a1\begin{vmatrix} x & x&1 \\ a_1 & b_1&1\\ a_2&b_2&1 \end{vmatrix}=0\\\ \\\Rightarrow x(b_1-b_2)-y(a_1-a_2)+b_2a_1-a_2b_1=0\\\Rightarrow x(b_2-b_1)-y(a_2-a_1)+a_2b_1-b_2a_1=0\\\Rightarrow x(b_2-b_1)+a_2b_1=y(a_2-a_1)+b_2a_1\\\text{Add }a_2b_2\ on\ both\ sides,\ we\ get\\\Rightarrow x(b_2-b_1)-a_2b_2+a_2b_1=y(a_2-a_1)-b_2(a_2-a_1)\\\Rightarrow (b_2-b_1)(x-a_2)=(a_2-a_1)(y-b_2)\\ \ \\ \Rightarrow\dfrac{y-b_2}{b_2-b_1}=\dfrac{x-a_2}{a_2-a_1}

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