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Answer to Question #19966 in Algebra for prince sharma
Question #19966
Proof that x^0=1
Expert's answer
We know, that:
(x^a)*(x^b) = x^(a+b)
1*x^b = x^b
So,
(x^0)*x^b = x^b => x^0=1
(x^a)*(x^b) = x^(a+b)
1*x^b = x^b
So,
(x^0)*x^b = x^b => x^0=1
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