a3x+5/ a3x-1
We need to solve a3x+5a3x−1\tfrac{a^{\smash{3x+5}}} {a^{\smash{3x-1}}}a3x−1a3x+5
We know that aman=am−n\frac{a^m} {a^n} =a^{\smash{m-n}}anam=am−n
So, a3x+5a3x−1=\tfrac{a^{\smash{3x+5}}} {a^{\smash{3x-1}}} =a3x−1a3x+5= a(3x+5)−(3x−1)a^{\smash{(3x+5) - (3x-1)}}a(3x+5)−(3x−1) =a3x+5−3x+1==a^{\smash{3x+5 -3x+1}} ==a3x+5−3x+1= a6a^6a6 (ans)
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