a3x+5/ a3x-1
We need to solve "\\tfrac{a^{\\smash{3x+5}}} {a^{\\smash{3x-1}}}"
We know that "\\frac{a^m} {a^n} =a^{\\smash{m-n}}"
So, "\\tfrac{a^{\\smash{3x+5}}} {a^{\\smash{3x-1}}} =" "a^{\\smash{(3x+5) - (3x-1)}}" "=a^{\\smash{3x+5 -3x+1}} =" "a^6" (ans)
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