Answer to Question #199331 in Algebra for Steezy

Question #199331

a3x+5/ a3x-1

1
Expert's answer
2021-05-28T06:04:02-0400

We need to solve "\\tfrac{a^{\\smash{3x+5}}} {a^{\\smash{3x-1}}}"


We know that "\\frac{a^m} {a^n} =a^{\\smash{m-n}}"


So, "\\tfrac{a^{\\smash{3x+5}}} {a^{\\smash{3x-1}}} =" "a^{\\smash{(3x+5) - (3x-1)}}" "=a^{\\smash{3x+5 -3x+1}} =" "a^6" (ans)








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