Rewriting the equation V = 2t + 1 t − 1 with t in terms of V , gives [1] t = 6 V . [2] t = V +1 V +2 . [3] t = 1−V V −2 . [4] t = V +1 V −2 .
Given equation is,
Cross multiplying
Taking common factor 't' outside,
So, right answer is option [4] t=V+1V−2\boxed{t=\dfrac{V+1}{V-2}}t=V−2V+1
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