Answer to Question #197889 in Algebra for tavlene

Question

Rewriting the equation V = 2t + 1 t − 1 with t in terms of V , gives [1] t = 6 V . [2] t = V +1 V +2 . [3] t = 1−V V −2 . [4] t = V +1 V −2 . 

Answer 1

Given equation is,

$V=\dfrac{2t+1}{t-1}$

Cross multiplying

$V(t-1)=2t+1\\\Rightarrow Vt-V=2t+1\\\Rightarrow Vt-2t=V+1$

Taking common factor 't' outside,

$\Rightarrow t(V-2)=V+1\\\Rightarrow t=\dfrac{V+1}{V-2}$

So, right answer is option [4] $\boxed{t=\dfrac{V+1}{V-2}}$