prove ln(xy)=ln(x)+ln(y)
"\\textbf{Prove:}"
Let "ln(xy)=c, ln(x)=a, ln(y)=b", then
"e^{c}=xy, \\, e^{a}=x, \\, e^{b}=y."
"e^{a+b}=e^{a}e^{b}=xy=e^{c}\\Rightarrow a+b=c" or "ln(x)+ln(y)=ln(xy)".
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