Question #197340

Inverse operations is a concept that needs to be understood because it is often used in algebra to solve variables.

We explain inverse operations as applied in numerical statements. Inspect the following example of a numerical equation, which is later translated into an algebraic equation:

21 × 5 - 10 = 95

21 × 5 = 95 + 10 (Add 10 both sides of =.)

21 = (Divide by 5 both sides of =.)

   Do the following:

Following our example to the left, work through the numerical equation below and then translate it into an algebraic equation, where you solve for the unknown value:

3/5 + 13 = 20

 


Expert's answer

35x+13=20\frac{3}{5}x+13=20

35x+13−13=20−13\frac{3}{5}x+13-13=20-13

35x=7\frac{3}{5}x=7

x=7×53x=7\times\frac{5}{3}

x=353x=\frac{35}{3}

x=11.67x=11.67


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