Answer to Question #195186 in Algebra for Amanda Coates

Question

Now try one of the problems on your own using the elimination/substitution method. 

You are hosting a study session at your house for you and your friends. You know that everyone will be getting hungry after you have worked hard for a few hours. Your mom wants to order pizza and you need to make sure that you get the perfect amount for everyone. Since you and your friends can eat a lot of pizza, you know that you will need 11 total pizzas. The three most popular toppings are cheese, pepperoni, and sausage and you know that you will need twice as many pepperoni pizzas as sausage pizzas. Your mom finds out that cheese pizzas cost $2.50, pepperoni cost $3.50, and sausage pizzas cost $3.00 (all of these prices include taxes and delivery fees). If she has a total of $35 to spend on the pizza, how many of each type should she order?

Answer 1

Let she order x type of cheese, y type of peperoni and z type of sausage pizza.

So, Total pizzas=11

$x+y+z=11~~~~~~~~-(1)$

Also, The per pizza costs is-

$2.5x+3.5y+3z\le 35~~~~~~~-(2)$

On solving the above equation using hit trial elimination method-

x=4,y=5,z=2