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Answer to Question #1931 in Algebra for James
Question #1931
2x[sup]3[/sup] + 3x[sup]2[/sup] - 8x -12 = 0& (given that 2 is a root)
Expert's answer
x1 = 2
(2x3 + 3x2 - 8x - 12)/(x-2) = 2x2 + 7x +6
2x2 + 7x +6 = 0
D = 49 - 48 = 1
x2 = -1.5
x3 = -2
(2x3 + 3x2 - 8x - 12)/(x-2) = 2x2 + 7x +6
2x2 + 7x +6 = 0
D = 49 - 48 = 1
x2 = -1.5
x3 = -2
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