Which represents the exponential form of log5(1/5)= -1
a. 1/5 5 = -1
b. 1/5-1= 5
c. 51/5 = -1
d. 5-1= 1/5
Given
log5(15)=−115=5−15−1=15log_5(\frac{1}{5})=-1\\\frac{1}{5}=5^{-1}\\5^{-1}=\frac{1}{5}log5(51)=−151=5−15−1=51
option d is correct
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