Question

Write out the log equation for this graph: y= log_base(x)

(0.25, -1)

(1,0)

(4,1)

(16,2)

Answer 1

First we have to calculate the value of base from the given points,

$\Rightarrow y= log_{b}x\\\Rightarrow b^y=x$

So from given point (0.25,-1)

$\Rightarrow b^{-1}=0.25\\\Rightarrow b=4$

So, above equation becomes $\boxed{y=log_4x}$

and Equation of above graph is: