Write the log equation for these coordinates: y= logbase(x)
(0.167, -1)
(1,0)
(6,1)
(36,2)
"y=log_{base}(x)"
(a)
"-1=log_{base}(0.167)"
"base^{-1}=0.167"
"\\frac{1}{base}=0.167"
"base=\\frac{1}{0.167}"
"base\\approx5.98"
therefore the logarithmic equation is:
"y=log_{5.98}(x)"
(b)
"0=log_{base}(1)"
"base^0=1...There\\space will\\space be\\space an\\space infinite\\space solution\\space for\\space the\\space base"
so, the base can be any number except 1 and negative numbers
in general, we can write,
"y=log(X)"
(c)
"1=log_{base}(6)\\\\base^1=6\\\\base=6"
Therefore the logarithmic equation is:
"y=log_6(x)"
(d)
"2=log_{base}(36)\\\\base^2=36\\\\base=6"
Therefore the logarithmic equation is:
"y=log_6(x)"
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