B. Evaluate the following algebraic expressions for the given value of x
1.2x—7 where x=4
Solution:
2.4x—8/3x+4 where x=—1
3.x²—6x+5 where x=—3
1. 2x-7
⇒ At x=4⇒2(4)−7=8−7=1\Rightarrow \text{ At } x=4 \Rightarrow 2(4)-7=8-7=1⇒ At x=4⇒2(4)−7=8−7=1
2.4x−83x+42. 4x-\dfrac{8}{3}x+42.4x−38x+4
at x=-1,
4(−1)−83(−1)+4=834(-1)-\dfrac{8}{3}(-1)+4=\dfrac{8}{3}4(−1)−38(−1)+4=38
3.x2−6x+5x^2-6x+5x2−6x+5
at x=-3,
(−3)2−6(−3)+5=9+18+5=32(-3)^2-6(-3)+5 =9+18+5=32(−3)2−6(−3)+5=9+18+5=32
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