Answer to Question #188813 in Algebra for Yasmin

Question #188813

f(x)=-2(x-1)^3(x+2)^2


1
Expert's answer
2021-05-07T11:49:02-0400

f(X)=2(x1)3(x+)2f(X)=-2(x-1)^3(x+)^2

=2(x313(3×x×1)(x+1)(x2+4+4x)=-2(x^3-1^3-(3\times x\times 1)(x+1)(x^2+4+4x)

=2(x313x(x1)(x2+4+4x)=-2(x^3-1-3x(x-1)(x^2+4+4x)

=[2x3+2+6x(x1)](x2+4+4x)=[-2x^3+2+6x(x-1)](x2+4+4x)

=[2x3+2+6x26x](x2+4+4x)=[-2x^3+2+6x^2-6x](x^2+4+4x)

=2x58x38x4+2x2+8+8x+6x4+24x2+24x36x324x24x2=-2x^5-8x^3-8x^4+2x^2+8+8x+6x^4+24x^2+24x^3-6x^3-24x-24x^2

=2x52x4+10x3+2x216x+8=-2x^5-2x^4+10x^3+2x^2-16x+8


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