Answer to Question #186674 in Algebra for Geetika

Question

Evaluate the following polynomial expression using Horner’s rule. Assume the value of x 

is 3. 

𝑃(𝑥) = 10 𝑥 power 5 + 6 𝑥 power 4 + 3 𝑥 power 3 − 6 𝑥 power 2 + 8𝑥 + 15  Show all the intermediate steps.

Answer 1

b₅ = 10 x 3 =30

b₄ = 6 + 3(30) = 96

b₃ = 3 + 3(96) = 291

b₂ = 6 + 3(291) =879

b₁ = 8+3(879) = 2645

b₀ = 15 +3(2645) = 7950

7950