If the graph of
y = log b x
passes through the point (8; 2), the value of b is
y=logbxb>0,b≠1,x>0(8,2)2=logb88=b2b=8b=22y=log_ {b}x\\ b>0, b\not =1, x>0\\ (8,2)\\ 2=log_{b}8\\ 8=b^{2}\\ b=\sqrt{8}\\ b=2\sqrt2y=logbxb>0,b=1,x>0(8,2)2=logb88=b2b=8b=22
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