Question #184780

(Log75 +Log9+Log5) ÷ (Log5 + Log45)


1
Expert's answer
2021-04-27T12:40:14-0400

(Log75+Log9+Log5)÷(Log5+Log45)=Log75∗9∗5Log5∗45=Log25∗3∗9∗5Log5∗9∗5=Log53∗33Log52∗32=Log153Log152=32=1.5(Log75 +Log9+Log5) ÷ (Log5 + Log45)={Log75*9*5 \over Log5*45}={Log25*3*9*5 \over Log5*9*5}={Log5^3*3^3 \over Log5^2*3^2}={Log15^3 \over Log15^2}={3 \over 2} =1.5


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