Answer to Question #184780 in Algebra for Irene Njeru

Question #184780

(Log75 +Log9+Log5) ÷ (Log5 + Log45)

Expert's answer

"(Log75 +Log9+Log5) \u00f7 (Log5 + Log45)={Log75*9*5 \\over Log5*45}={Log25*3*9*5 \\over Log5*9*5}={Log5^3*3^3 \\over Log5^2*3^2}={Log15^3 \\over Log15^2}={3 \\over 2} =1.5"

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