Write the inequality , 3/2<x+1<7/2 in the modulus form
Given that
"\\frac{3}{2}<x+1<\\frac{7}{2} \\newline\n\n\\therefore\\:\\frac{3}{2}-1<x+1-1<\\frac{7}{2}-1"
"\\frac{1}{2}<x<\\frac{5}{2}"
The range of x belong to (1/2 , 5/2).
Now,
"\\qquad \\frac{1}{2}<x<\\frac{5}{2}\\newline\n\\therefore \\quad \\frac{1}{2}-\\frac{3}{2}<x-\\frac{3}{2}<\\frac{5}{2}-\\frac{3}{2} \\newline\n\\therefore \\quad -1<x-\\frac{3}{2}<1\\newline\n\\therefore \\quad |x-\\frac{3}{2}|<1"
Hence the given ineqaulity "\\frac{3}{2}<x+1<\\frac{7}{2}" in the modulus form is "|x-\\frac{3}{2}|<1"
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