Answer to Question #175177 in Algebra for Max

Question

Operations on Functions

Given k(x)= √x^2-8 and p(x)=2x^2

What is k ∘ p?

Given h(x)=2000-0.32x, k(x)= √x^2-8 and m(x)=5+7x^3

What is h ∘ k ∘ m?

Thank you so much!

Answer 1

1.

$$k\circ p=\sqrt{(2x^2)^2-8}=\sqrt{4x^4-8}$$

$$k\circ p=\sqrt{4x^4-8}$$

Or

$$k\circ p=2\sqrt{x^2-2}$$

2.

$$h\circ k\circ m=2000-0.32\sqrt{(5+7x^3)^2-8}$$