Question #173797

(x - 2)(x - 2i)(x + 2)(x - 2i) is equal to

Expert's answer

(x−2)(x−2i)(x+2)(x−2i)(x - 2)(x - 2i)(x + 2)(x - 2i)

=(x2−4)(x2−4i−4)=(x^2-4)(x^2-4i-4)

=x4−4x2i−4x2−4x2+16i+16=x^4-4x^2i-4x^2-4x^2+16i+16


=x4−8x2+16−(4x2−16)i=x^4-8x^2 +16-(4x^2-16)i


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Canada #340153 on Dec 2023